Write a function in the form y=mx+b for the line that contains the points (-6.4, -2.6) and (5.2, 9)

First solve for the slope, m using the two points given. It doesn't matter which point you choose as point 1 or 2 as long as you're consistent.

m = (y2 - y1)/(x2 - x1)

point 1: (–6.4, –2.6)

point 2: (5.2, 9)

m = (9 - -2.6)/(5.2 - -6.4)
m = (9 + 2.6)/(5.2 + 6.4)
m = 11.6/11.6
m = 1

put the newly found slope into the linear equation for m

y = (1)x + b
y = x + b

Now solve for the y-intercept, b
by putting one of the given points

9 = 5.2 + b

b = 9 - 5.2
b = 3.8

final equation:

y = x + 3.8

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