Find tan (a+B), given cot a= -3/4 , csc B= 25/24 , 90° < a < 180° , 90°< B < 180°

tan(a + B) =

Step-by-step explanation:

cot(a) =

Therefore, tan(a) =

cosec(B) =

Since, 1 + cot²(B) = cosec²(B)

1 + cot²(B) =

cot²(B) =

cot(B) =

          =

tan(B) =

Since, tan and cot of an angle is negative in II quadrant,

Therefore, tan(B) =

Since, tan(a + B) =

By substituting the values in the identity,

tan(a + B) =

                =

                =

                =

                =

Therefore, tan(a + B) = is the answer.

14

step-by-step explanation:

14 x 3 = 42