What is the equation of the line that is perpendicular to the given line and passes through the point (2, 6)?

Step-by-step explanation:

The given line is parallel to X-axis, so its equation is y = b (b is its intersect of Y-axis)

Therefore the perpendicular line has to be parallel to Y-axis, so its equation will be x = x₀, where x₀ is its intersect of X-axis and x-coordinate of any point it passes through.

(2, 6)      ⇒     x₀ = 2

so the equation is

                             x = 2

- 1.613 = -1.6 or -1.61

-1.522 = -1.5 or -1.52

0.587 = 0.6 or 0.59

3.079 = 3.1 or 3.08