Consider the radical equation = c + 2. Which statement is true about the solutions c = 3 and c = –6? The solution c = 3 is an extraneous solution. The solution c = –6 is an extraneous solution. Both c = 3 and c = –6 are true solutions. Neither are true solutions to the equation.

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1

eww xbox also eww dayz

step-by-step explanation:

just for that im not answering

the answer is b: 18

step-by-step explanation:

use the pythagorean theorem to .

a^2+b^2=c^2

plug 18 for "r"

the 2 legs are 18 and 24

18^2+24^2=c^2

324+576=c^2

900=c^2

c=30

30-12=18

18 is the radius

: )