Given: EFGH is a rectangle

Prove: Segment FH is congruent to Segment GE

Step-by-step explanation:

                  Statements                            Reasons

1). FGH is a rectangle                  1). Given

2). EFGH is a parallelogram       2). a. All rectangles are parallelogram

3). EF ≅ b. GH                            3). Opposite sides of a parallelogram are

                                                        equal in measure

4). EH ≅ EH                                 4). c. Reflexive property

5). ∠FEH and ∠GHE are the      5). d. Property of a rectangle

    right angles        

6). ∠FEH ≅ e. ∠GHE                  6). Right angle theorem

7). ΔFEH ≅ ΔGHE                       7). f. SAS postulate of congruence

8). FH ≅ GE                                 8). g. CPCTC (corresponding parts of

                                                          congruent triangles are congruent)

f

step-by-step explanation:

f

ye

step-by-step explanation: