Find the two numbers who's sum is 68 and
who's difference is 106.

55 and 23

Step-by-step explanation:

x+y=78 & (2):x−y=32,(x>y).

(1)+(2)⇒2x=110⇒x=55.

(1),y=78−55=23.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."