Write an equation of the line that passes through (3,2) and is perpendicular to the line y= 1/3x-3

Step-by-step explanation:

Given equation:

By comparing this to intercept form  , where m= slope , c=y-intercept.

Let n= slope of required line.

[Product of slope of two per perpendicular line =-1 ]

Equation of line passes through (a,b) and have slope m:

Equation of required line :

Hence, equation of the required line: y= -3x+11

let x and 400 - x be the two numbers.  

==> 0.80x + 0.85(400 - x) = 400 - 68 from the statement of the problem.  

< ==> 0.80x + 0.85(400 - x) = 400 - 68  

==> 340 - 0.05x = 332  

< ==> -0.05x = -8 ==> x = 160, the first number ==> 400 - x = 240, the second number.