The density of aluminum is 2.70 g/cm3. A square piece of aluminum foil, 22.86 cm on a side is found to weigh 2.568 g. What is the thickness of the foil, in millimeters?

0.133 mm

Step-by-step explanation:

From the question,

Density (D) = mass (m)/Volume (V) Equation 1

D = m/V

make V the subject of the equation

V = D×m Equation 2

Given: D = 2.7 g/cm³, m = 2.568 g

Substitute into equation 2

V = 2.7(2.568)

V = 6.934 cm³.

But,

Thickness (n) = Volume/Area

n = V/A Equation 3

Where A = Area of the square foil  = 22.86² = 522.58 cm²

n = 6.934/522.58

n = 0.0133 cm.

n = 0.133 mm

the answer is 48m^2!

step-by-step explanation:

correct answer is c. just did it

step-by-step explanation: