Someone help pleasee

Option (3)

Step-by-step explanation:

If the sides of a triangle are unequal then the measure of sides opposite to these angle will be in the order from least to greatest.

In ΔABC,

m∠CAB = 180°- (m∠B + m∠C)

        = 180° - (25° + 27°)

        = 180° - 52°

        = 128°

Since, ∠CAB > ∠ABC  ∠ACB

Therefore, a > b > c ---------(1)

Now from ΔADB,

m∠BAD + m∠ADB + m∠DBA = 180°

32° + m∠ADB + m∠35° = 180°

m∠ADB = 180° - 67°

             = 113°

Since, m∠ADB > m∠DBA > m∠BAD

Therefore, c > d > e -------(2)

Combining both the inequalities,

a > b > c > d > e  

Option (3) will be the answer.

step-by-step explanation:

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