1.the equation of line cd is (y−3) = − 2 (x − 4). what is the slope of a line perpendicular to line cd? 2.the equation of line ab is y = 2x + 4. write an equation of a line parallel to line ab in slope-intercept form that contains point (3, −2). 3.the equation of line qr is y = negative 1/2x + 1. write an equation of a line perpendicular to line qr in slope-intercept form that contains point (5, 6). 4.line wx contains (−1, 2) and (4, 12) line yz contains points (5, 8) and (−2, −6). lines wx and yz are 5.line cd contains points a (4, −7) and b (4, 8). the slope of line cd

So here's how to do it,
slope intercept form is y=mx+b
m is the slope, b is the y- intercept, X is your unknown variable.

you need to solve to get y by its self to get your slope.

for perpendicular lines flip the slope

ex 1, smy=2x+6 --- slope of a perpendicular line will be 1/2

ex 2, y=3/2+8 ---8 perpendicular lien would have a slope of 2/3

parallel lines have the same slope so any equation with with the same slope will be parallel if it has the same degree.

ex. y=2x+14 is parallel to y= 2x+56

slope can be found using the following formula if you have two sets of points on the same line

m= y2-y1 ÷ X2 - X1

Dis the solution here