Solve the simultaneous equation 2x+3y=4 3x+2y=11

y = - 2, ; x = 5

Step-by-step explanation:

Given :

2x+3y=4 - - (1)

3x+2y=11 - - (2)

From (1)

2x + 3y = 4

2x = 4 - 3y

x = (4-3y) / 2 = 2 - 3/2y

In (2)

3x + 2y = 11

3(2 - 3/2y) + 2y = 11

6 - 4.5y + 2y = 11

6 - 2.5y = 11

-2.5y = 11 - 6

-2.5y = 5

y = - 2

Put y = 2 in (2)

3x + 2(-2) = 11

3x - 4 = 11

3x = 11 + 4

3x = 15

x = 5

i believe the answer is 68cm

step-by-step explanation:

i just took 34 x 2 because the space between v and y is the same as y to k.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐