Can someone help me asapp

he has 10 type of each coin

Step-by-step explanation:

Total number of cents in possession is calculated as;

= 25 + 10 + 5

= 40 cent

Total amount in possession = $4

                                               = 400 cent

Since he has equal number of each cent, let this equal number be "y";

40cent (y) = 400cent

40y = 400

divide both sides by 40

Therefore, he has 10 type of each coin

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15