Including Jose, there are eight people in his family. If order matters, how many ways can he arrange his family members into a row of five seats if Jose must sit in the first seat?

840 ways

Step-by-step explanation:

From the above question, we are told that order matters, hence, to solve the above question, we use the Permutation formula.

P(n, r) = nPr = n!/(n -r)!

From the above question,

Since Jose is included in the 8 people and he takes the first seat

n = 8 - 1 = 7 people

r = 5 - 1 = 4 seats

This is because, once Jose takes the first seat, there are 4 seats left with 7 people waiting to be seated

Hence,

7P4 = 7!/(7 - 4)!

7P4 = 7!/3!

7P4 = 5040/6

7P4 = 840 ways

when studying polynomials, you often hear the terms zeros, roots, factors and x x the multiplicity of a zero is important because it tells us how the graph of the let's look at the graph of a function that has the same zeros

step-by-step explanation:

answer: the answer is 35%