At a grocery store, there is a 62% chance that a customer will pay with a credit card and a 25% chance that a customer will pay with cash. 12% of the customers uses both ways to pay. What is the probability that a randomly selected customer will pay with a credit card or with cash?

The probability that a randomly selected customer will pay with a credit card or with cash

P(CD ∪C ) = 0.75 = 75%

Step-by-step explanation:

Explanation:-

Given the chance that a customer will pay with a credit card

P(CD) = 62 % =0.62

Given the chance that a customer will pay with a cash

P(C) = 25% =0.25

Given the chance that a customer will pay both

P(CD ∩ C) = 12% = 0.12

The probability that a randomly selected customer will pay with a credit card or with cash

P(CD ∪C ) = P( CD ) + P(C) - P( CD∩C)

                = 0.62+0.25 -0.12

               = 0.75

Final answer:-

The probability that a randomly selected customer will pay with a credit card or with cash

P(CD ∪C ) = 0.75

it is 570

step-by-step explanation:

i need points

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