A technical machinist is asked to build a cubical steel tank that will hold 410 L of water. Calculate in meters the smallest possible inside length of the tank. Round your answer to the nearest .001 .

0.743 m

Step-by-step explanation:

Given that :

Volume of cubical tank = 410 L

Volume of a cube = L³

First we convert 410 L into meter cube

1 L = 10^-3 m³

1L = 0.001 m³

410 L = (410 * 0.001) m³

410 L = 0.410 m³

0.410 = l^3

Cube root of both sides

(0.410)^1/3 = l

0.7428958 = l

l = 0.7428958 m

Hence, smallest possible inside length of the cube would be : 0.743m

(23*2)-12=x     x=34

step-by-step explanation: