HJ is extended through point J to point K, \text{m}\angle JHI = (x+12)^{\circ}m∠JHI=(x+12)

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, \text{m}\angle HIJ = (x-3)^{\circ}m∠HIJ=(x−3)

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, and \text{m}\angle IJK = (5x-6)^{\circ}m∠IJK=(5x−6)

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. Find \text{m}\angle IJK. m∠IJK.

19 degrees

Step-by-step explanation:

From the question given

The interior angles are x+12 and x - 3

Exterior angle is <IJK = 5x-6

Using the rule that states that the sum of interior angle of a triangle is equal to the exterior

<JHI + <HIJ = <IJK

x+12 + x-3 = 5x - 6

2x+9 = 5x -6

2x - 5x = -6-9

-3x = -15

x = -15/-3

x = 5

Get <IJK

Recall that <IJK = 5x - 6

<IJK = 5(5) - 6

<IJK = 25-6

<IJK = 19 degrees

Hence the measure of <IJK is 19 degrees

answer: a.   one is a factor of every whole number since every number is divisible by itself.

that is the sum

step-by-step explanation:

there are no other answers without knowing the variables values