Based on a study by Dr. P. Sorita Soni at Indiana University, assume that eye colors in the United States are distributed as follows: 40% brown, 35% blue, 12% green, 7% gray, 6% hazel. If three people are randomly selected, what is the probability that one will have brown eyes, one will have gray eyes, and one will have green eyes (with replacement)

Answer

0.00336

Step-by-step explanation:

Given :

P(Brown), P(Br) = 0.4

P(Blue) = P(b= 0.35

P(green,) = P(g) = 0.12

P(gray), P(Gr) = 0.07

If 3 individuals are selected, the probability that one has brown eye, 1 has Grey and one has green.

Since the probabilities are independent :

P(Br) * P(Gr) * P( g)

0.3 * 0.07 * 0.12

= 0.00336

1     3    

step-by-step explanation:

hopefully im right

= 5

step-by-step explanation:

to find the 15th term substitute n = 15 into the nth term formula

= (- 3 × 15 ) + 50 = - 45 + 50 = 5