From a random sample of workers at a large corporation you find that 58% of 200 went on a vacation last year away from home for at least a week. What is the margin of error for the 95% confidence interval of (0.50, 0.66) of coworkers who went on a vacation last year away from home for at least a week

The margin of error for the confidence interval is of 0.08 = 8%.

Step-by-step explanation:

A confidence interval has two bounds, an upper bound and a lower bound. The margin of error is half the subtraction between these two bounds.

In this question:

Lower bound: 0.5

Upper bound: 0.66

Margin of error: (0.66 - 0.5)/2 = 0.16/2 = 0.08

The margin of error for the confidence interval is of 0.08 = 8%.

options a,b,c are the right answer.

step-by-step explanation:

a linear parent function is always represented as y = x

if we write this function in the form of y=mx+c

⇒

or  

now if we plot a graph we will find these characteristics:

1) y intercept of the graph is zero so its a straight line passing through origin.

2) as we can see in both the forms of function written, values of x and y may be either positive or negative for the positive slope means points on the graph are either in first quadrant or in third one.

3) it's slope is one.

i think is g(1)=-1.

hope that i can