From earlier studies, it is believed that the percentage of students favoring a four-day school week during May and June of every school year is approximately 85%. What is the minimum sample size that will create a margin of error of 2% with 90% confidence

The minimum sample size 'n' = 862.538

Step-by-step explanation:

Step(i):-

Given the percentage of students favoring a four-day school week during May and June of every school year is approximately 85%

Given the Proportion of students favoring a four-day school week during May and June of every school year

      p = 85% = 0.85

      q = 1-p = 1-0.85 = 0.15

Given Margin of error = 2 % or 0.02

Level of significance = 0.90 or 0.10

The critical value Z₀.₁₀ = 1.645

Step(ii):-

The Margin of error is determined by

Cross Multiplication, we get

         √n = 29.369

squaring on both sides, we get

         n = 862.538

Final -

Sample size 'n' = 862.538

isaiah walks 3 miles due north, turns and then 5 miles due east. how far is he from his starting point?

a^2 + b^2 = c^2

let c = distance from starting point.

(3)^2 + (5)^2 = c^2

9 + 25 = c^2

34 = c^2

sqrt{34} = sqrt{c^2}

sqrt{34} = c