use the discrminant to determine all values of k which would result in the equation -3x^2-6x+k=0 having real, unequal roots. must be right ty helppp asap

Step-by-step explanation:

We have the equation:

Where a = -3, b = -6, and c = k.

And we want to determine values of k such that the equation will have real, unequal roots.

In order for a quadratic equation to have real, unequal roots, the discriminant must be a real number greater than 0. Therefore:

Substitute:

Simplify:

Solve for k:

So, for all k greater than -3, our quadratic equation will have two real, unequal roots.

Notes:

If k is equal to -3, then we have two equal roots.

And if k is less than -3, then we have two complex roots.

i can't see the picture : /