Write an equation of a line in slope-intercept form that passes through (-3,5) and is parallel to y = -6x +1. Then find its x- and y-intercepts.

a) The equation of the Parallel line to the given straight line is

       6 x + y + 13 =0

b) Slope - intercept form

        y = - 6 x - 13

c) The intercept - form

x - intercept  =  

y - intercept = - 13

Step-by-step explanation:

Step(i):-

Given the equation of the straight line

                             y = -6x +1

                  6 x + y - 1 = 0

The equation of the Parallel line to the given straight line is

                6x + y + k=0 and it passes through the point (-3, 5 )

           ⇒ 6 (-3 ) + 5 + k =0

          ⇒  - 18 + 5 + k=0

         ⇒   -13 + k = 0

        ⇒     k = 13

The equation of the Parallel line to the given straight line is

       6 x + y + 13 =0

Step(ii):-

Slope - intercept form

                y = m x + C

                y = - 6 x - 13

Step(iii):-

Intercept - form

              6 x + y + 13 =0

              6 x + y = - 13

The intercept - form

x - intercept  =  

y - intercept = - 13

n=9

step-by-step explanation:

7 times a number = 7n

decreased by 13 = 7n-13

same as is =

5 times the number = 5n

increased by 5 = 5n+5

7n-13 = 5n+5

2n=18

n=9

d

step-by-step explanation:

i used the pitagoras theoreme