Point K is on line segment \overline{JL} JL . Given JK=2x-2,JK=2x−2, KL=x-9,KL=x−9, and JL=2x+8,JL=2x+8, determine the numerical length of \overline{KL}. KL .

KL = 10

Step-by-step explanation:

Point K is on line segment \overline{JL} JL . Given

JK=2x−2

JL=2x+8

KL=x-9

JL = JK + KL

Hence:

2x + 8 = 2x - 2 + x - 9

2x + 8 = 2x + x - 2 -9

2x + 8 = 3x - 11

Collect like terms

3x - 2x = 8 + 11

x = 19

We are to find the numerical length of KL

KL = x - 9

KL = 19 - 9

KL = 10

the radius is 2 times the diameter.

step-by-step explanation: