Raul empuja su auto de 950 KG sobre una pista rugosa e inclinada 15,0 con una fuerza paralela a la pista, cuya magnitud es de 200 N. Determina el trabajo mecanico hecho por el peso sobre el auto para un desplazamiento de 5,00m (gravedad=10m/5)

966 joules

Step-by-step explanation:

Step one:

given data

mass of car= 950kg

angle of incline= 15°

Applied force= 200N

displacement = 5m

If we apply a force on an object through a distance work is done, hence Mechanical work is the product of a force applied on an object and its displacement while that force is applied

Step two:

Work done= Force * distance

Since the car is moved on an inclined plane, the expression for the work done is

Work-done= Frcos∅

where r is the distance moved

Work-done= 200*5cos 15

Work-done= 200*4.83

Work-done= 966 joules

$3,200 x 7.25% = $3,200 x .0725 = $232 interest monthly

$232 monthly x 12 annual = $2, 784

step-by-step explanation:

i believe it is 0.1m because the measurement of 30.4m limits how precise you can be

you can only be as precise as the least precise measurement