Help please! area of rectangles and squares.

Step-by-step explanation:

area of rectangle

height×base

(2x-5)(2x-2)=

=4x^2-4x-10x+10

=4x^2-14x+10

(we get quadratic equation)

a=4 b=-14 c=10

firat find discriminant with formula:

D=b^2-4ac(-14)^2-(4×4×10)=196-160=36

now find x1 and x2 with formula:

X=(-b±√D)/2a

x1=(14+√36)/8=20/8=2.5

x2=(14-√36)/8=8/8=1

lets put values :

if we put x2 value as a base, which is 1 in given height and base, we will get 2(1)-2=0. measure of amy side can't be 0.

and if we put x2 in height, it will give us zero.

so no matter which one we put as value. we will get 0cm^2. so i think it cant be detected. im sorry if im wrong

-14 is the answer

hope this : ))

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.