PLZZ HELP !! Select the correct answer. What are the zeros of the function y= (x-4)(x^2 - 12x+36) A. -6,4 and 6
B. 4 and 6
C. -6 and -4
D. 0, 4, and 6

The zeroes of any function are where the function touches or passes through the x-axis.

To find these zeroes, we can factor, and set each part equal to 0.

y = (x - 4)(x^2 - 12x + 36)

It looks like some of the factoring was already done for us! All we have to do is factor the quadratic. To do so, we need two numbers that multiply to equal (a * c) and add up to b. In this case those two numbers are -6 and -6.

y = (x - 4)(x - 6)(x - 6)

Finally, set each part equal to 0!

x - 4 = 0

x = 4

x - 6 = 0

x = 6

x - 6 = 0

x = 6

Therefore, the zeroes of the function are 4 and 6, option B.

Hope this helps!! :)

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step-by-step explanation: