Find the value of x.

PLEASE HELP

The value of x is 6

Step-by-step explanation:

AAS postulate of congruence is:

In the given figure

∵ JKL and JML are two triangles

∵ ∠K and ∠M are right angles

∴ ∠K ≅ ∠M

∵ ∠JLK and ∠JLM have the same mark

∴ ∠JLK ≅ ∠ JLM

∵ JL is a common side in the 2 triangles

∴ JL = JL

→ BY using the AAS postulate above

∴ ΔJKL ≅ ΔJML

→ From the result of congruency

∴ JK = JM

∵ Jk = 2x - 4

∵ JM = 4x - 16

→ Equate them

∴ 4x - 16 = 2x - 4

→ Subtract 2x from both sides

∴ 4x - 2x - 16 = 2x - 2x - 4

∴ 2x - 16 = -4

→ Add 16 to both sides

∵ 2x - 16 + 16 = -4 + 16

∴ 2x = 12

→ Divide both sides by 2

∴ x = 6

50*10 is greater

step-by-step explanation:

if you add the zero from 10 to 50, it will give you a bigger number.