A, B, C and D are four towns. B is 30 kilometres due east of A. C is due 30 kilometres north of A. D is due 45 kilometres of A. Work out the bearing of B from C.

Complete question :

A, B, C and D are four towns. B is 30 kilometres due east of A. C is due 30 kilometres north of A. D is due 45 kilometres due south of A. Work out the bearing of B from C.

44°

Step-by-step explanation:

From the diagram sketched, we have a right angled d triangle, thus we can apply Pythagoras ;

Using the relation :

Tanθ = opposite / Adjacent

Tan θ = 30 / 30

Tanθ = 1

θ = tan^-1(1)

θ = 45°

Hence, bearing of B from C is 45°

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

the two may have that, even a breakdown is probably offered