Roscoe hit a ball straight up at a speed of 96 ft/s. His bat hit the ball at a height 3 ft above the ground. After how many seconds did the ball hit the ground? (Give your answer to the nearest hundredth of a second.)

t = 6.031 seconds

Step-by-step explanation:

Roscoe hit a ball straight up at a speed of 96 ft/s.

His bat hit the ball at a height 3 ft above the ground.

We need to find how many seconds did the ball hit the ground.

Using equation of motion to find height of the ball.

When it hits the ground.

h = 0

It is a quadrctic equation where a = -16, b = 96 and c = 3

Neglecting negative value.

So, after 6.031 seconds the ball will hit the ground.

Given :

Roscoe hit a ball straight up at a speed of 96 ft/s.

His bat hit the ball at a height 3 ft above the ground.

To Find :

After how many seconds did the ball hit the ground.

Solution :

When the ball reaches the same height from which it is thrown ( i.e. 3 ft ) its displacement will be zero.

So, using equation of motion :

Now, time taken to reach ground from 3 feet of height is :

t = 0.03 s

Therefore, time taken is T = 19.2 + 0.03  = 19.23 seconds.