X An airplane climbs at an angle of
16° with the ground. Find the
ground distance the plane travels
as it moves 2500 m through the
air.
Help me

Step-by-step explanation:

We can form a right triangle and use trigonometry for a right triangle to solve this. The ground distance the plane travels is its displacement in the x-direction. The 2500 meters the plane moves through represents the hypotenuse of right triangle, and the ground distance is the adjacent leg of the angle. Therefore, we set up the following equation:

, where is the ground distance.

Solving, we get .

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