What are the coordinates of A after a dilation of 2/3 centered at the origin? Question 11 options: A' =(−3/4, −3/2)

A' = (4/3, 2/3)

A' = (2, 1)

A' =(2/3, 2/3)

The image of A(2, 1) after dilation by a scale factor of 2/3 will be: A'(4/3, 2/3) .

Step-by-step explanation:

Given

We know that when an object is dilated by a scale factor, it gets reduced, stretched, or remains the same, depending upon the value of the scale factor.

Rule to calculate the dilation by a scale factor 2/3 centered at the origin

P(x, y) → P'(2/3x, 2/3y)

Here, P'(2/3, 2/3y) is the image of P(x, y).

Thus,

A(2, 1) → A'(2/3(2), 2/3(1)) = A'(4/3, 2/3)

Therefore, the image of A(2, 1) after dilation by a scale factor of 2/3 will be: A'(4/3, 2/3) .

(0,,,0)

step-by-step explanation:

the table of x and y values is shown in the attached pic(part of question)

we have to decide according that graph

given points are (0, 0) (–1, 0), (2, 0)

when we graph these points on graph they show an increasing line as shown in the attached pic

step-by-step explanation:

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