What is the equation of the line that has a slope of 13 and goes through the point (6,−2)? y=13x−8

y=13x

y=13x−4

y=13x+4

{Or, if you mean slope of 1/3:  y = ¹/₃x - 4 }

Step-by-step explanation:

The point-slope form of the equation is y - y₀ = m(x - x₀), where (x₀, y₀) is any point the line passes through and m is the slope:

m = 13

(6, -2)    ⇒   x₀ = 6,  y₀ = -2

The point-slope form of the equation:

y + 2 = 13(x - 6)

So:

y + 2 = 13x - 78        {subtract 2 from both sides}

y = 13x - 80            ←  the slope-intercept form of the equation

{Or, if you mean slope of ¹/₃:  m = ¹/₃

The point-slope form of the equation: y + 2 = ¹/₃(x - 6)

y + 2 = ¹/₃x - 2         {subtract 2 from both sides}

y = ¹/₃x - 4             ←  the slope-intercept form of the equation}

the least common denominator is 40

step-by-step explanation:

their are no angles. sorry cant .