If sinθ = 4/5 and cosθ < 0, then tanθ =
a. -4/3
b. -3/4
c. 3/4
d. 5/4
e. 4/3

Step-by-step explanation:

Since cot²θ + 1 = csc²θ,

we have cot²θ + 1 = [1 / (4/5)]².

=> cot²θ + 1 = 25/16

=> cot²θ = 9/16

=> cotθ = -3/4 (as sine is +ve and cosine is -ve)

=> tanθ = -4/3. (A)

2

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.