The amusement park has two plans available for the school to choose from. Plan A is listed in the table below. Cost (per vehicle) Cost (per person)
$10 $30

The cost of Plan B can be calculated using the formula c = $15v + $28p, where c represents the cost, v represents the number of vehicles, and p represents the number of people. The school has a budget of $7200 for the cost of tickets and parking. If 241 students are going on the field trip, which plan should the school purchase? Explain your reasoning.

the second plan should be purchased.

Step-by-step explanation:

school budget is $7200

plan 1: 241 students are $30 each is

241 × 30 = $7230 which is over budget with no money for parking for the vehicles.

plan 2: 241 students are $28 each is

241 × 28 = $6748

with a budget of $7200 for the trip the amount left for parking is

$7200 - $6748 = $452

plan 2: Parking is $15 per vehicle

Therefore the remaining $452 can be used to pay for 452 ÷ 15 = 30.13 vehicles

The school should purchase Plan 2 for the field trip.

The budget of $7200 can pay for 241 tickets for students and parking for 30 vehicles

the graph in the attached figure

step-by-step explanation:

we have

using a graphing tool

the graph in the attached figure

the roots are ( x-intercepts) x=-0.5,x=1,x=3

the y-intercept is the point (0,3)