X + 3x² – 28x

Can you guys help me solve this in ax^2+bx+c
Thank you thank you

3x²+(-27x) +0

Step-by-step explanation:

The given expression is :

x + 3x² – 28x

We need to solve this in the form of ax²+bx+c.

we can write the given expression as :

3x²-28x+x = 3x²-27x

= 3x²+(-27x) +0

If we compare the given expression with the general expression, we find that,

a = 3, b = -27 and c = 0

Hence, the required equation is 3x²+(-27x) +0.

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

x = 17

step-by-step explanation:

in the given figure, two triangles are inscribed in a circle where ∠bae ≅ ∠dae which makes the side be and de equal so we can write it as:

3x - 24 = x + 10

solving this equation for x to get:

3x - x = 10 + 24

2x = 34

x = 34/2

x = 17

therefore, the value of x = 17.