Find a number, twice of which decreased by 7 gives 65.

Number = 36

Step-by-step explanation:

Given that,

A number twice of which decreased by 7 gives 65.

Let the number be x.

Twice of the number is 2x.

ATQ,

2x - 7 = 65

We can solve the above equation.

Adding 7 both sides.

2x-7+7 = 65 +7

2x = 72

x = 36

So, the required number is 36.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3