Marta is solving the equation S = 2πrh + 2πr2 for h. Which should be the result? StartFraction S Over 2 pi r EndFraction equals h. – r = h
StartFraction S minus r Over 2 pi r EndFraction equals h. = h
S – S minus StartFraction r Over 2 pi EndFraction equals h. = h
S – S minus StartFraction 2 pi Over r EndFraction equals h. = h

Here the answer LOL

Step-by-step explanation:

Step-by-step explanation:

Only the term 2πrh contains h.  Isolate this term on the right by subtracting 2πr^2 from both sides:

S - 2πr^2 = 2πrh

Now divide the left side by 2πr, obtaining:

        s - 2πr^2

h =  

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐

1e+27

step-by-step explanation: