Y-intercept for y=2(x-3)^2+4

The y-intercept for this equation is 22.

Step-by-step explanation:

You can solve this quite easily by assigning a zero value to x and solving for y.  That is where the curve will intersect the x-axis:

y = 2(x - 3)² + 4

y = 2(x² - 6x + 9) + 4

y = 2x² - 12x + 18 + 4

y = 2x² - 12x + 22

EDIT

Note that the expression above is in standard form, though it can also be factored if needed:

y = 2(x² - 6x + 11)

Now we can solve for an x value of zero:

y = 2(0)² - 12(0) + 22

y = 22

So the y-intercept is 22.

noncoplanar points are points that do not lie on the same line.

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step-by-step explanation:

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i believe both

no, tati didnt over exaggerate

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