A triangle has two side lenths of 1 and 16 what is the largest possible whole-number length of the third side?

16

Step-by-step explanation:

Given that:

Length of two sides of the triangle = 1 and 16 ;

The largest possible whole-number length of the third side would be ;

Recall from triangle inequality theorem; the length of any two sides of a triangle is greater than the third side. Therefore. The largest possible whole number value the third side could have is:

Assume the third side is the largest :

Then, the third side must be less than the sum of the other two sides ;

Third side < (16 + 1)

Third side < 17

Therefore, the closest whole number lesser than the sum of the other two sides is (17 - 1) = 16

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).