A gate is made up of a rectangle and a semicircle, as shown. Find the area of the gate. Use 3.14 for .Round your answer to the nearest tenth

797.0ft²

Step-by-step explanation:

Find a related diagram attached

Area of the gate = Area of the semicircle + Area of the Rectangle

Area of the semicircle = πr²/2

r is the radius

From the diagram, radius r = 20/2 = 10ft

Area of the semicircle = 3.14(10)²/2

Area of the semicircle = 3.14(100)/2

Area of the semicircle = 314/2

Area of the semicircle = 157ft²

Area of the rectangle = Length * Width

Area of the rectangle = 20*32

Area of the rectangle = 640ft²

Area of the gate = 157 + 640

Area of the gate = 797ft²

Hence the area of the gate is 797.0ft²

darn right!

step-by-step explanation:

steve kerr's sons name is let that skin in.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it