Two trucks are traveling in the same direction, one going twice as fast as the other. At the end of 6 hours they are 204 miles apart. How fast is each traveling?

34 mph and 68 mph respectively

Step-by-step explanation:

Step one:

given data

let the speed of the first truck be x mph

and the speed of the second truck be 2x mph

time taken = 6 hours

total distance = 204 miles

Step two:

from speed = distance/time

distance= speed*time

hence

2x*6-6x= 204

12x+6x= 204

6x= 204

divide both side by 6

x= 204/6

x=34 mph

The second truck was moving at

=2x

=2*34

=68 mph

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.