One positive number is 4 more than the other, and the sum of their squares is 208. what are the numbers? i need !

You can use equations to solve this question.

The first number is this: 4 + x
The other number: x
So:
(4 + x)² + x² = 208 (solve the parentheses squared)
4² + x² + x² = 208 (add like terms and simplify the exponents)
16 + 2x² = 208 (subtract 16 on both sides)
2x² = 192 (divide by two on both sides)
x² = 96 (square root both sides)
x = √96
√96 = 4√6

The first number: 4 + 4√6
The other number: 4√6

CHECK YOUR WORK:
(4 + 4√6)² + (4√6)² = 208
4² + (4√6)² + (4√6)² = 208
16 + 96 + 96 = 208
208 = 208

THE NUMBERS ARE 4√6 AND 4 + 4√6
(unless you are required to simplify 4 + 4√6, that is the answer)

The answer would be a i think