Solve the quadratic equation numerically (using tables of x- and y- values). x squared + 2 x + 1 = 0

a. x = -1
b. x = 1 or x = -3
c. x = -3
d. x = 2 or x = -1

sorry but thanks for points!!1

check the picture below.

well, the angle at the vertex d is clearly not a right-angle, let's check for the one at the vertex f which does look like,   however if it's indeed, that means ef is perpendicular to df, in which case their slopes will be negative reciprocal of each other.

so the negative reciprocal of the slope of ef is 1, however the slope of df is not 1, is 1/2, so nope, they're not perpendicular lines.

x+y = 29, 5x + 2y = 100

step-by-step explanation:

i'm guessing it was a multiple first option was the correct answer