Compare the line passing through the points (-2, 9) and (4, 6) to the line given by the equation y= 2/5 x -4.

No relation ( see bottom for detail )

I'm not sure if you want this explanation, but here you go.

Step-by-step explanation:

If you want to find out if the points are on this line, substitute in the values.

y = 2/5x - 4               y = 2/5x - 4

6 = 2/5 ( 4 ) - 4         9 = 2/5 ( -2 ) - 4

6 = 8/5 -4                 9 = -4/5 - 4

6 = 8/5 - 20/5           9 = -4/5 - 20/5

6 ≠ -12/5                    9 ≠ -24/5

After substituting in the values, I've come to the conclusion that these points don't pass through this line.

Solving to find if they are perpendicular, I use the rise/run equation-

y_2 - y_1 over x_2 - x_1

y_2 and x_2 is the second set of points, which then can help determine the slope of two points.

6 - 9

4 - ( negative 2 )    ( this is also equal to adding a positive 2 )

-3 / 6

= -1/2 is the slope of these two points

Comparing the slopes given, I can conclude that the equation and these two points have no relation.

asnwer is (g o h o f)(x) = 2x - 6/x + 7

step-by-step explanation:

given,

f(x) = x - 3/x

g(x) = x + 3

h(x) = 2x + 1

we need to find : (g o h o f)(x)

we can write (g o h o f)(x) = g[ h{ f(x) } ]

so first we find h{f(x)}

h{f(x)} = f(x) + 3 = (x - 3/x) + 3

h{f(x)} = x - 3/x + 3

now we find g[ h{ f(x) } ].

g[ h{ f(x) } ] = g(x - 3/x + 3)       {plug h{f(x)} = x - 3/x + 3 in g[h{f(x)}] }

g(x - 3/x + 3) = 2 (x - 3/x + 3) + 1

                    = 2x - 6/x + 6 + 1

                    = 2x - 6/x + 7

hence we get (g o h o f)(x) = 2x - 6/x + 7