2) Mrs. Dias has 3 children. What is the probability that the first, second, and third child will all be girls?

1/8.

Step-by-step explanation:

Since there are only two gender you can be born in from birth (boy or girl) we have 1/2 chance that the first child will be a girl.

The second child will also have 1/2 of being a girl, and the third child too will have 1/2 chance of being a girl.

Multiple them all together, and what you get will be the answer.

(1/2) * (1/2) * (1/2) = 1/8

NOTE: THIS IS UNDER THE ASSUMPTION THAT MRS. DIAS HAS 1/2 CHANCE OF RECIEVING A GIRL.

IN A REAL LIFE SITUATION, THIS WOULD PROBABLY BE VERY RARE, SINCE WOMEN USUALLY HAVE A TENDENCY TO BIRTH EITHER MORE SONS THAN DAUGHTERS OR MORE DAUGHTERS THAN SONS.

This means that women usually have a higher probability to birth sons than daughters, or have a higher probability to birth more daughters than sons.

However, to have equal chances... that's pretty rare.

However, since this is a math question, I just assumed that there would be equal chances of getting a girl or boy since the question never said the probability of getting a girl was for Mrs. Dias.

7/2

(decimal: 3.5)

welcome ; )

step-by-step explanation:

it would not be increasing by nothing that i can see probably by 25 percent that is all i can sat\y for now if i have any thing else to say i will edit this.

step-by-step explanation: