If you were to use the quadratic formula to solve (identify the zeros) this equation, what would happen? `y\ =\ x^{2}\ +\ 6x\ +\ 10`

Step-by-step explanation:

The best way to answer this is to graph it before using the quadratic formula. The graph is shown below.

Notice that the minimum doesn't come anywhere near the x axis. That means when you use the quadratic formula, you  are going to get the square root of a negative number. Check out the discriminate.

√(b^2 - 4*a * c)

a = 1

b = 6

c = 10

√(36 - 4*1*10

√36 - 40

√-4

2*i

So there is no point going any further. You have no real roots.

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