Graph the line that has a slope of 6 and includes the point (0,4).

The equation of the line with slope 6 and containing the point (0, 4) will be:

The graph of the line y = 6x+4 is attached below.

Step-by-step explanation:

The slope-intercept form of the line equation

where

m is the slopeb is the y-intercept

Given

The slope m = 6The point (0, 4)

The y-intercept can be determined by setting x = 0 and determining the corresponding value of y.

The point (0, 4) indicates that:

at x = 0, y = 4

Thus, the y-intercept b = 4

now substituting b = 4 and m = 6 in the slope-intercept form of the line equation

Thus, the equation of the line with slope 6 and containing the point (0, 4) will be:

The graph of the line y = 6x+4 is attached below.

Intersecting secant-tangent theorem states that if a tangent segment and a secant segment are drawn to a circle from an exterior point, then the square of the measure of the tangent segment is equal to the product of the measures of the secant segment and its external secant segment.so to break it down: 1. pq acts as the tangent and ps as the secant with an intersection at p.sr = 21rp = 3x + 3pq = 4x + 4following to equation: tangent squared = the two segments multiplied by each otherso (4x + 4) ^ 2 = (3x + 3) • (21) simplifies to 16x^2 - 31x - 47 = 0 or (16x - 47)(x + 1) x = -1 or x = 47/162. pq acts as the tangent and ps as the secant with an intersection at p (again! )sr = 16rp = xpq = 15(15) ^ 2 = 16 • x225 = 16xx = 225/163. the interesting chords are proportional to each other so a ratio is possible to set up: ap dp 10 3 + x = = —— = pc pb 8 xcross multiple to get 10x = (3 + x)(8)x = 12