If angle A is congruent to itself by the Reflexive property, which transformation could be used to prove triangle ABC is similar to triangle ADE by AA similarity postulate? A. Translate triangle ADE so that point D lies on point B to confirm angle D is congruent to angle B.

B. Translate triangle ADE so that point B lies on point E to confirm angle B is congruent to angle E.

C. Dilate triangle ABC from point A by the ratio segment AD over segment AB to confirm segment AD is similar to segment AB

D. Dilate triangle ABC from point A by the ratio segment AE over AC to confirm segment AE is similar to segment AC.

A. Translate triangle ADE so that point D lies on point B to confirm angle D is congruent to angle B.

Step-by-step explanation:

Two triangles are said to be similar if the ratio of their corresponding sides are equal.

The AA Similarity Postulate states that If two angles of one triangle is congruent to two angles of another triangle, then the two triangles are similar.

Translation is the movement of a point up, down, left or right.

Since ∠A = ∠A (reflexive property of congruence)

We have to prove that ∠D = ∠B, by Translating triangle ADE so that point D lies on point B

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step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)