Pls help. First person to answer correctly will get brainliest. Compute the modulus and argument of each complex number.
part 1. 1 + i
part 2. 4 - 4i
part 3. 2 + 5i
part 4. 2(cos(2pi/3) + isin(2pi/3))

1+i +1-i

4-4i =4+4i

2+5i=2-5i

2(-1/2+i3/2

Step-by-step explanation:

no, the equation would be invalid since they are both not equal.

step-by-step explanation:

here you got

4y-6+4y 2-9

first, you would simplify the equation on the form.

4y-6+4y 2-9

then, move all the terms that contains a y to the left and all the other terms to the right.

+4y-4y+-9-6

finally, you will simplify the left and the right side of the equation.

y=-3