PLSS HELP ASAP
write the equation of a line with a slope of -1/3 that passes through (-4,8)

y = -1/3 x + 6 2/3

Step-by-step explanation:

y = mx + b      m = - 1/3

(-4,8)   x = -4   y = 8

y intercept (b) = y - mx = 8 - (-1/3)*(-4) = 8 - 4/3 = 6 2/3

equation: y = -1/3 x + 6 2/3

- 2 + 10x³ - 21x² + 19x - 4

step-by-step explanation:

each term in the second factor is multiplied by each term in the first factor

x²(- 2x² + 4x - 1) - 3x(- 2x² + 4x - 1) + 4(- 2x² + 4x - 1) ← distribute

= - 2 + 4x³ - x² + 6x³ - 12x² + 3x -8x² + 16x - 4

collect like terms

= - 2 + 10x³ - 21x² + 19x - 4 ← in standard form

square root

step-by-step explanation: