bh ( b is the base and h the perpendicular height )
= 12
![\displaystyle \frac{hb}{2} = A\:OR\:\frac{1}{2}hb = A \\ \\ \frac{[16][12]}{2} = \frac{192}{2} = 96\:OR\:\frac{1}{2}[16][12] = \frac{1}{2}[192] = 96](/tpl/images/1026/7989/9736a.png)
What is the area of the unshaded region of the rectangle? part 1. Show work please
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Mathematics, 11.01.2021 20:20 trammellb91
What is the area of the unshaded region of the rectangle? part 1. Show work please
Answers: 1
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